Solve Coloumbs Law Problem: Mass & Charge of 2 Particles

In summary, two equally charged particles with a mass of 6.3x10^-7 kg and an initial acceleration of 7.0m/s^2 and 9.0m/s^2, respectively, are held 3.2x10^-3 m apart and released from rest. Using Coulomb's law and Newton's second law, the mass of the second particle can be determined. The charges of both particles are assumed to have the same magnitude, making it possible to find the individual charges using Coulomb's law.
  • #1
th3plan
93
0

Homework Statement



Two equally charged particles are held 3.2x10^-3 m apart and then released from rest. The initial acceleration of the first particles is observed to be 7.0m/s^2 and that of the second to be 9.0 m/s^2. If the mass of the first particle is 6.3x10^-7 kg , what are a.) the mass of the second particle, and b) the magnitude of the charge on each particle.



Homework Equations



Coloumbs Equation

The Attempt at a Solution



kinda need some help how to start this problem.
 
Physics news on Phys.org
  • #2
Use Newton's second law here to get the force associated with the 1st particle. Note that the force exerted by the 1st on the 2nd is the same as the one by the 2nd on the first. From here you can find a). Hm is that all you're given? Because I don't see how you can find the individual charges. Both particles are released at the same time?

EDIT: Sheesh, should have read it more closely. The question states that both charges have the same magnitude. In that case, just use Coulomb's law to find it.
 
  • #3
th3plan said:

Homework Statement



Two equally charged particles are held 3.2x10^-3 m apart and then released from rest. The initial acceleration of the first particles is observed to be 7.0m/s^2 and that of the second to be 9.0 m/s^2. If the mass of the first particle is 6.3x10^-7 kg , what are a.) the mass of the second particle, and b) the magnitude of the charge on each particle.

Homework Equations



Coloumbs Equation

The Attempt at a Solution



kinda need some help how to start this problem.

OK what are the variables in Coulomb's Equation?
 
  • #4
What does Coloumb's law say about the force on the two particles? What does Newton's laws say about the force on the two particles? Will the forces bring them together or push them apart? Start with this. If you can't get it, make a post showing what you tried using these laws and someone will probably provide more information.
 

What is Coloumb's Law?

Coloumb's Law is a fundamental law in physics that describes the electrostatic interaction between two charged particles. It states that the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

How do you solve a Coloumb's Law problem involving the mass and charge of two particles?

To solve a Coloumb's Law problem, you will need to use the formula F = k(q1q2)/r^2, where F is the force, k is the Coulomb's constant, q1 and q2 are the charges of the particles, and r is the distance between them. You will also need to convert the masses of the particles into charges using the formula q = m/√(2e), where m is the mass and e is the elementary charge. Once you have substituted all the values into the formula, you can solve for the force.

What is the Coulomb's constant?

The Coulomb's constant, denoted by k, is a proportionality constant that relates the electrostatic force between two charged particles to their charges and the distance between them. Its value is approximately 8.99 x 10^9 Nm^2/C^2.

What is the unit of charge used in Coloumb's Law?

The unit of charge used in Coloumb's Law is the Coulomb (C). It is defined as the amount of charge that passes through a point in an electric circuit in one second when the current is one ampere.

Can Coloumb's Law be applied to objects with non-point-like charges?

Yes, Coloumb's Law can be applied to objects with non-point-like charges. In such cases, the distance between the charges is measured from their centers of charge. Additionally, the total charge of the object can be calculated by summing the charges of its individual components.

Similar threads

  • Introductory Physics Homework Help
Replies
1
Views
5K
  • Introductory Physics Homework Help
Replies
26
Views
576
  • Introductory Physics Homework Help
2
Replies
42
Views
3K
  • Introductory Physics Homework Help
Replies
13
Views
962
  • Introductory Physics Homework Help
Replies
6
Views
666
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
2K
  • Introductory Physics Homework Help
Replies
15
Views
3K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
1K
Back
Top