(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The charges and coordinates of two charged particles held fixed in an xy plane are q1 = +3.5 µC, x1 = 1.5 cm, y1 = 0.50 cm, and q2 = -4.0 µC, x2 = -2.0 cm, y2 = 1.5 cm.

(a) Find the magnitude of the electrostatic force on q2. Done I got this part =

94.98868N

(b) Find the direction of this force. Got this also =

-15.9453959° (counterclockwise from the +x axis)

(c) At what coordinates should a third charge q3 = +5.5 µC be placed such that the net electrostatic force on particle 3 due to particles 1 and 2 is zero?

Can't get this - saw problem solving methods for questions that are very similar in previous postings, but I can't get the math to work out

2. Relevant equations

Got as far as q1/x^2 = q2/(x+r)^2

r being the distance between q1 and q2 since q3 must lie to the right of q1

3. The attempt at a solution

many attempts at a solution - but its been 15 years since I have done significant math and I can't get anywhere now.

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# Homework Help: Coloumbs Law

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