Calculate the Force between Charges

[wizard.ubit]

Homework Statement

Find the magnitude of the force b/w charges

(1,2,3) (5,-2,4)

() ()
5 micro Columb 6 micro columb
charge 1 charge 2

The Attempt at a Solution

Vector r = (5-1)i + (-2-2)j + (4-3)k
Vector r = 4i -4j + k

Magnitude of Vector r = Square root (4^2 + (-4)^2 + 1^2)

Magnitude of Vector r = square root (33) or 5.744


a/c to columbs law

F= (9x10^9) (5x10^-6 ) (6x10^ -6 ) (4i-4j+k)
5.744 ^3 (cube b/c unit vector )

F= 0.27 { what should i do of ( 4i-4j+k )
5.744^3


what should i do please i hve got paper on WeDnesday Help me

 

[rl.bhat]

Hi wizard.ubit, welcome to PF.
In the problem only magnitude is required.
So F = k*q1*q2/d^2

 

[tomcue]

Dear student,

Thank you for your question. To calculate the force between charges, we can use Coulomb's Law, which states that the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

In this case, we have two charges, one with a magnitude of 5 micro Columb and the other with a magnitude of 6 micro Columb. The distance between them can be calculated using the vector r that you have already found. However, we need to convert the magnitude of r from meters to centimeters in order to match the units of the charges (micro Columb is 10^-6 coulomb).

So, the magnitude of r is 5.744 x 10^-2 cm. Plugging this into Coulomb's Law, we get:

F = (9 x 10^9) * (5 x 10^-6) * (6 x 10^-6) * (5.744 x 10^-2)^-2

F = 0.27 N

The unit vector (4i - 4j + k) indicates the direction of the force. In this case, it is a unit vector pointing from the first charge to the second charge. We can use this information to determine the direction of the force.

I hope this helps. Good luck on your paper!