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Introductory Physics Homework Help
Comapring acceleration of person in elevator
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[QUOTE="songoku, post: 4988175, member: 171861"] [h2]Homework Statement [/h2] Two persons, each having mass 70 kg, stand in identical elevators. One stand normally, one hangs in the ceiling of elevator. How is the acceleration of them when the elevators move? a. Equal in magnitude and direction b. Equal in magnitude and opposite in direction c. Different in magnitude but equal in direction d. Different in magnitude and direction e. Not enough information[h2]Homework Equations[/h2] F = m.a [h2]The Attempt at a Solution[/h2] I assume the second person hangs on a rope attached to the ceiling of the elevator so there are two forces acting on the man, weight and tension. There are also two forces acting on the man who stands in the elevator, weight and normal force. Assuming the elevators move upwards, the acceleration experienced by each man is: a = (T - W) / m and a = (N - W)/m We don't know the exact value of T and N, so the answer will be "not enough information"? Thanks [/QUOTE]
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Introductory Physics Homework Help
Comapring acceleration of person in elevator
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