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## Homework Statement

Three identical resistors are connected in parralel. The equivalant resistance increases by 700 ohm when one resistor is removed and connected in series with the remaining two, which are still in parrallel. Find resistance of each resistor

R

_{t1}+ 700ohms = R

_{t2}

## Homework Equations

(1/R

_{t}) = (1/R

_{1}) + (1/R

_{2}) ... For a parallel Circuit

R

_{t}= R

_{1}+ R

_{2}... For a series Circuit

## The Attempt at a Solution

First, we made an equation for the initial parallel circuit

RT1 +700 = RT2

1/Rt1 =1/R + 1/R +1/R

1/Rt1=3/R

1/R

_{t}= 3/R

R = 3R

_{t}for later substitution

RT1 +700 = RT2

1/Rt1 =1/R + 1/R +1/R

1/Rt1=3/R

For the combination circuit..

RT2 = 2/R + R

We substituted the RT1 and RT2 into R's

RT1 +700 = RT2

R/3 + 700 = R/2 + R

After plugging it in, we get 600 for R. Is this correct?