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I have this for Discrete homework:

A lock has the numbers from 0 to 59 .......A combo is made up of 3 numbers.......How many combos are possible if the 2nd and 3rd numbers have to differ by at least 3

The answer is whatever 60 times 58 times 57 is

I know why the 60 is there..because the 1st number can be any of the 60. How they got 58 times 57 I'm not exactly sure.....

Can anyone help?

Anton

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# Homework Help: Combination Lock

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