- #1
oNesterud
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Hi! Me and some guys at work has a little argue about how many combinations you can have after that you have throwed away the first globe in bowling. There are 10 pins and 10 postions for them to stand. Are there any quations that works out for this?
Here's an example of all the 10 pins, rised at all 10 positons:
x x x x
.x x x
..x x
...x
(I hope this is the right thread caus its not an homework)
Here's an example of all the 10 pins, rised at all 10 positons:
x x x x
.x x x
..x x
...x
(I hope this is the right thread caus its not an homework)
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