- #1
Unto
- 128
- 0
This is just my own practise question.
I have a relationship of
r = [tex]\frac{D}{2}[/tex]sin4[tex]\theta[/tex]
The apparent error formula is now:
[tex]\left(\frac{\Lambda r}{r}\right)^{2}[/tex] = [tex]\left(\frac{\Lambda D}{D}\right)^{2}[/tex] + 16 [tex]\left(\frac{\Lambda \theta}{tan 4 \theta}\right)^{2}[/tex]
Using a standard combination of errors formula, I only get
[tex]\left(\frac{\Lambda r}{r}\right)^{2}[/tex] = [tex]\left(\frac{\Lambda D}{D}\right)^{2}[/tex] + 16 [tex]\left(\frac{\Lambda \theta}{4 \theta}\right)^{2}[/tex]
Since I know there would be an error in the measurement of the angle. The 16 I'm also unsure of anyway, I just guessed you had to square the 4 and put it on the outside. How to you do errors for trigonometric identities is what I want to know. How do you go from sin to tan and what is the reasoning behind what they did and came out with?
Here is the error formula I think I am supposed to use
[tex]\left(\frac{\Lambda F }{F}\right)^{2}[/tex] = [tex]k^{2} \left(\frac{\Lambda A}{A}\right)^{2}[/tex] + [tex] l^{2} \left(\frac{\Lambda B}{B}\right)^{2}[/tex]
Thank you for any help
I have a relationship of
r = [tex]\frac{D}{2}[/tex]sin4[tex]\theta[/tex]
The apparent error formula is now:
[tex]\left(\frac{\Lambda r}{r}\right)^{2}[/tex] = [tex]\left(\frac{\Lambda D}{D}\right)^{2}[/tex] + 16 [tex]\left(\frac{\Lambda \theta}{tan 4 \theta}\right)^{2}[/tex]
Using a standard combination of errors formula, I only get
[tex]\left(\frac{\Lambda r}{r}\right)^{2}[/tex] = [tex]\left(\frac{\Lambda D}{D}\right)^{2}[/tex] + 16 [tex]\left(\frac{\Lambda \theta}{4 \theta}\right)^{2}[/tex]
Since I know there would be an error in the measurement of the angle. The 16 I'm also unsure of anyway, I just guessed you had to square the 4 and put it on the outside. How to you do errors for trigonometric identities is what I want to know. How do you go from sin to tan and what is the reasoning behind what they did and came out with?
Here is the error formula I think I am supposed to use
[tex]\left(\frac{\Lambda F }{F}\right)^{2}[/tex] = [tex]k^{2} \left(\frac{\Lambda A}{A}\right)^{2}[/tex] + [tex] l^{2} \left(\frac{\Lambda B}{B}\right)^{2}[/tex]
Thank you for any help