There are 5 possible choices for the first shoe, 4 for the second, 3 for the third, and 2 for the fourth, resulting in a total of 5 x 4 x 3 x 2 = 120 different combinations.
No, in this problem, each shoe is considered as an individual item, so a pair of shoes cannot be counted as one choice.
The formula for calculating combinations is nCr = n! / (r! x (n-r)!), where n represents the total number of items and r represents the number of items being chosen.
No, the order of the chosen shoes is not important in this problem. As long as the same 4 shoes are chosen, it does not matter in which order they are selected.
No, in this problem, each shoe can only be chosen once. The combination is made up of unique items and does not allow for repetition.