# Combination problem

A group consists of 5 boys and 8 girls. In how many ways can a team of four boys be chosen, if the team contains.

no more than one boy

So my attempt was this. I thought to myself well if I fix one girl and calculate the number on combination 5 boys can be chosen for 3 spaces which is 10, I would then multiply that by 8 to get the ans. So my ans comes out to be 80 , but the ans in back to the book comes out to be 85 any thoughts?

PeroK
Homework Helper
Gold Member
2020 Award
A team of four boys with no more than one boy makes no sense.

A team of four boys with no more than one boy makes no sense.
My bad I ment no more than one girl. I was looking at the question below when typing this.

PeroK
Homework Helper
Gold Member
2020 Award
My bad I ment no more than one girl. I was looking at the question below when typing this.
A team of four boys has no girls in it!

Do you mean a team of four with no more than one girl?

A team of four boys has no girls in it!

Do you mean a team of four with no more than one girl?
yes. Let me re write the question.

A group consists of 5 boys and 8 girls. In how many ways can a team of four be chosen, if the team contains

no more than one girl.

PeroK
Homework Helper
Gold Member
2020 Award
yes. Let me re write the question.

A group consists of 5 boys and 8 girls. In how many ways can a team of four be chosen, if the team contains

no more than one girl.
So, the team might have no girls in it?

Ah I don't know if you ask that question to lead me to the ans or it as an actual question, but I just realised what the question is asking me. So there is 80 combinations of having 1 girl on the team but the questions ask for no more therefore I would have to include the number of combinations for all boys i.e 5 so 80+5=85

PeroK