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Combination problem

  1. Oct 25, 2016 #1

    A group consists of 5 boys and 8 girls. In how many ways can a team of four boys be chosen, if the team contains.

    no more than one boy

    So my attempt was this. I thought to myself well if I fix one girl and calculate the number on combination 5 boys can be chosen for 3 spaces which is 10, I would then multiply that by 8 to get the ans. So my ans comes out to be 80 , but the ans in back to the book comes out to be 85 any thoughts?

    Big thanks in advance.
     
  2. jcsd
  3. Oct 25, 2016 #2

    PeroK

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    A team of four boys with no more than one boy makes no sense.
     
  4. Oct 25, 2016 #3
    My bad I ment no more than one girl. I was looking at the question below when typing this.
     
  5. Oct 25, 2016 #4

    PeroK

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    A team of four boys has no girls in it!

    Do you mean a team of four with no more than one girl?
     
  6. Oct 25, 2016 #5
    yes. Let me re write the question.

    A group consists of 5 boys and 8 girls. In how many ways can a team of four be chosen, if the team contains

    no more than one girl.
     
  7. Oct 25, 2016 #6

    PeroK

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    So, the team might have no girls in it?
     
  8. Oct 25, 2016 #7
    Ah I don't know if you ask that question to lead me to the ans or it as an actual question, but I just realised what the question is asking me. So there is 80 combinations of having 1 girl on the team but the questions ask for no more therefore I would have to include the number of combinations for all boys i.e 5 so 80+5=85
     
  9. Oct 25, 2016 #8

    PeroK

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    That looks like the missing 5 teams in any case!
     
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