A group consists of 5 boys and 8 girls. In how many ways can a team of four boys be chosen, if the team contains.
no more than one boy
So my attempt was this. I thought to myself well if I fix one girl and calculate the number on combination 5 boys can be chosen for 3 spaces which is 10, I would then multiply that by 8 to get the ans. So my ans comes out to be 80 , but the ans in back to the book comes out to be 85 any thoughts?
Big thanks in advance.