1. The problem statement, all variables and given/known data As shown in the diagram below (not to scale), a 3.0 cm high object is placed 50.0 cm from thin converging lens A that has a focal length of 10.0 cm. Converging lens B with a focal length of 15.0 cm is placed 25.0 cm to the right of lens A. Find and describe the final image. http://webct6.nic.bc.ca/webct/RelativeResourceManager/Template/CourseMaterials/CourseContent_2007FA/Assignments/PHY060W_Assignment_09_files/image013.jpg [Broken] 2. Relevant equations 1/di = 1/f - 1/do 3. The attempt at a solution 1/ dia = 5/50.0cm - 1/50.0cm= 1/12.5 cm dia=12.5cm dob= 25.0cm - 12.5 cm = 12.5 cm fb= 15.0cm 1/dib= 1/15.0cm- 1/12.5cm= 12.5/187.5 - 15.0/187.5= -2.5/ 187.5 dib= -75 so now to my question. I am not sure what a negative distance indicates when dealing with a combination of lenses. does it mean the image is virtual? because I know from my diagram that it is on the opposite isde of the lenses from where the light is coming.