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Three pairs: Two cards of the same value. another 2 of a differnt value, and a 3rd paid of a third value. i.e Q(clubs) Q(diamonds) 6(hearts) 6(diamonds) 4(spades) 4(hearts)

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For my attempt I started with 13C3 + 12C3 +11C3 ... + 3C3 = 1001 different hands

But this hasn't accounted for the differnt variation of suits, threre are 6 possible pairs of suits, so i multiply 1001 by 6?

thanks for any help!