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Combinatorial mathematics

  1. May 17, 2010 #1
    1. The problem statement, all variables and given/known data How many different bridge hands are possible containing five spaids, three diamonds, three clubs, and two hearts?




    2. Relevant equations



    3. The attempt at a solution
    Total number of hands in which I can get 5 spaids is 13C5
    Total number of hands in which I can get 3 diamonds is 13C3
    Total number of hands in which I can get 3 clubs is 13C3
    Total number of hands in which I can get 2 hearts is 13C2
    Adding these up gives 1937 which is not any where close to 8,211,173,256.
    Help?
     
  2. jcsd
  3. May 17, 2010 #2

    Mark44

    Staff: Mentor

    Those would be "spades."
    Multiply all four numbers together and you get the right result.
     
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