Combinatorics: seating people (1 Viewer)

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so this is what I am stuck on:
In how many different ways can you seat 11 men and 8 women in a row so that no two women are to sit next to each other.

I know it's going to be combination and not permutation and that total number of seating them is 11!*8! but that is as far as I could get :frown:

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