- #1
mojo4king
- 10
- 0
for eg. combustion of CH4:
CH4(g) + 2O2(g) ---> CO2(g) + 2H2O(l)
enthalpy of combustion: (-393.51) + 2(-241.82) - (-74.81) = -802.34 kj/mol
energy output per unit mass:
802.34 x 1000/16(molar mass) = -50146.25 kj/kg
energy output per unit volume:
-50146.25 x 0.645(mass density) = -32344.33 kj/m3
However I have no clue on how to calculate the carbon dioxide output per unit mass and volume, any help would be kindly appreciated.
Many thanks.
CH4(g) + 2O2(g) ---> CO2(g) + 2H2O(l)
enthalpy of combustion: (-393.51) + 2(-241.82) - (-74.81) = -802.34 kj/mol
energy output per unit mass:
802.34 x 1000/16(molar mass) = -50146.25 kj/kg
energy output per unit volume:
-50146.25 x 0.645(mass density) = -32344.33 kj/m3
However I have no clue on how to calculate the carbon dioxide output per unit mass and volume, any help would be kindly appreciated.
Many thanks.