Common emitter amplifier circuit using feedback biasing

  • Engineering
  • Thread starter denian
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  • #1
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i don't have the basic of analog, but i tried to look for in the books. unfortunately, the books are using voltage divider biasing instead of feedback biasing.

i have a circuit like this:

http://www.mrnerdy.com/forum_img/BJTampfeedbackbiase.jpg

would anyone tell me the flow of the current in the circuit, and made gain possible?
 
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Answers and Replies

  • #2
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In DC, the caps are open circuits. Rc's current is given by

[tex]I = \frac {V_2 - V_c}{R_c}[/tex]

Current going through Rb is given by

[tex]I_b = \frac {V_c - V_b}{R_b}[/tex]

Since this is common emitter, then [itex]V_e = 0[/itex], then assume its forward biased then [itex]V_b = 0.7[/itex].

Current going into the collector is

[tex]I-I_b = \beta I_b[/tex]
 

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