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Common mode signals

  1. Feb 27, 2014 #1
    Why is it necessary for the gain magnitudes of inverting and non- inverting ends to be equal in magnitudes to be able to reject the common mode signal?

    Also can someone explain the ratio obtained of voltage divider in difference amplifier.

    R4/R4+R3[1+R2/R1]= R2/R1 Where,

    R1 input resistance, R2 feedback resistor, R3 and R4 are voltage dividers used to attenuate the positive gain.
    Last edited: Feb 27, 2014
  2. jcsd
  3. Feb 28, 2014 #2


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    This seems very much a homework-type question.

    Vout = A+*V+ - A-*V-

    For the resistor ratios, draw the circuit, establish the effect of the "virtual earth", derive the applicable equations, and manipulate the algebra.
  4. Feb 28, 2014 #3
    because your sine waves have to be out of phase 180 degrees in order to reject the common mode noise, if the gain is different it will clip the sum. maybe someone else could elaborate on this.
  5. Feb 28, 2014 #4


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    Intuitively (and trivially): The common mode signal is an identical signal applied to both the + and - inputs, so obviously if the gains are different the inputs will not cancel each other.

    But, NOxy is correct, you should grind through the equations and see why this is true. I will say I dislike the term "virtual earth". I'd rather say "just assume that the + and - inputs will be at equal voltages". That will always be true in an ideal amplifier if the output is not saturated.

    There is nothing to explain about the resistor ratio equation (if what you wrote was correct). You just need to work through it for a couple of examples to understand it forever. Nothing I can explain will replace working it out yourself. It's only hard the first time.
  6. Mar 2, 2014 #5


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    An ideal OpAmp is a differential amplifier. If you are working on that basis and then you find it will amplify A+B, the resulting output will not be what you want. It would mean, at the trivial level, that you would need to get the input bias voltage 'exact'.

    I fully endorse meBig Guy's advice that:
  7. Mar 2, 2014 #6
  8. Mar 2, 2014 #7

    jim hardy

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    I'm late to the party...

    so will just reinforce the advice to bite the bullet and do the algebra.

    Solve the circuits for voltage at inverting and non-inverting inputs of the IC.
    You'll get an equation for each input.
    Set those voltages equal,
    because that's how operational amplifiers work - they force their inputs equal,
    and it is the job of the designer to surround the amplifier with a network that lets it do that.

    If it cannot make them equal, it can't "operate".

    So Vinverting = f1(a lot of resistors),
    and Vnoninverting = f2(a lot of resistors)

    Set the two functions equal one another,
    The resulting equation should lead directly to your resistor ratios.

    old jim
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