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Forums
Physics
Quantum Physics
Commuting observables vs. exchanging measurements
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[QUOTE="greypilgrim, post: 5697956, member: 490763"] I'm not talking about the commutator being zero (meaning the zero operator), but its expectation value being zero for a given state $$\left\langle \psi|[A,B]|\psi\right\rangle=0\enspace .$$ I might not have worded this very well in #1 though, I made some clarifications. [/QUOTE]
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Forums
Physics
Quantum Physics
Commuting observables vs. exchanging measurements
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