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Comparison of work on A and B

  • Thread starter gijungkim
  • Start date
  • #1
50
2

Homework Statement


The same constant force is used to accelerate two carts of the same mass, initially at rest, on horizontal frictionless tracks. The force is applied to cart A for twice as long a time as it is applied to cart B. The work the force does on A is WA; that on B is WB. Which statement is correct?

a.WA = WB.

b.WA = https://www.physicsforums.com/x-apple-ql-id://75E1D3CA-C6B4-441B-A5A4-36B84CE66FF0/x-apple-ql-magic/C3C64FB0-9E65-46A8-9150-27D9512B39A1.pdf [Broken]WB.

c.WA = 2 WB.

d.WA = 4 WB.

e.WB = 2WA.

Homework Equations


W = F * d * cos(theta)
x= vot + 0.5 *a * t^2

The Attempt at a Solution


The answer is D, but I don't know where to start to get the answer d.
I thought since it has same mass and acceleration, twice of time will just make it twice of work.
Can anyone help me explaining this with equation??
 
Last edited by a moderator:

Answers and Replies

  • #2
50
2
Oh oh I think I got it. Is it because
x = Vot + 0.5at^2 and when I times 2 on t, the x will become 4x and it will eventually make 4 times more work right???
 
  • #3
6
6
How do you figure that the answer is d? Where did you get that answer from?
 
  • #4
6
6
Also those kinematic equations should have been posted in relevant equations if you are still using them in class. If you are doing kinematics, then use that equation.
 
  • #5
50
2
How do you figure that the answer is d? Where did you get that answer from?
Oh I was studying Energy part by myself and I downloaded a random one in the internet! They have questions with answers, but no solution so if I don't know how to solve it, I just have to ask here to get an advice.
 
  • #6
50
2
Also those kinematic equations should have been posted in relevant equations if you are still using them in class. If you are doing kinematics, then use that equation.
Haha yeah I'm not in kinematic right now and didn't know I was going to use that equation here. After thinking I kinda figured out I might able to use kinematic equation, but wasn't 100 percent sure if I could, so I wrote in reply. Sorry haha
 
  • #7
6
6
Oh I understand. I think it is great that you are teaching yourself physics! I think the kinematic is your best bet in this case because it is the only way you can take velocity and acceleration into account. Good job. :)
 
  • #8
50
2
Oh I understand. I think it is great that you are teaching yourself physics! I think the kinematic is your best bet in this case because it is the only way you can take velocity and acceleration into account. Good job. :)
Thank you! :)
 

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