# Comparison test for series

1. Jun 3, 2014

### uzman1243

I'm trying to find if this series converges or diverges using the comparison test:

and the answer goes:

My problem is, Im not sure how to go from 1/2^(n+1) to 1/2(1/2)^n.

can you please explain that to me

File size:
6.3 KB
Views:
86
File size:
9.3 KB
Views:
87
2. Jun 3, 2014

### Matterwave

$$\frac{1}{2^{n+1}}=\frac{1}{2\cdot 2^n}=\frac{1}{2}\frac{1}{2^n}=\frac{1}{2}\left(\frac{1}{2}\right)^n$$