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Compex roots

  1. Oct 24, 2007 #1
    [SOLVED] Compex roots

    1. The problem statement, all variables and given/known data
    state the number of complex roots of each equation, then find the roots and graph the related function.

    x^2 + 25 = 0

    2. Relevant equations



    3. The attempt at a solution
    x^2 + 25 = 0

    so there are 2 complex roots. Once I have established that then I minus the 25 to the other side.

    x^2 = -25

    square root both sides.

    x = +/-5i

    I'm pretty sure everything up to this point is correct but the thing I did above I think it is wrong. Firstly because if there are two complex roots and I already have one of them what is the other one. I'm confused, so please help me. thank you.
     
    Last edited: Oct 24, 2007
  2. jcsd
  3. Oct 24, 2007 #2

    rock.freak667

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    Homework Helper

    you have both roots...x=+5i and x=-5i ....it is correct
     
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