you yust did complete the square. you only have a term of the form (x-A)^2 left and terms that do not depend on x.x^2 + y^2 - 2pxy = (x-py)^2 - (py)^2 + y^2
can someone please help me with this. i totally forgot how to do completing the square.
I tried uploading a figure about my previous post; not sure it will work.yeah...thats my teacher doing that..
i just want to refresh my memory on how that work..
i still dont understand...can you clearly described the steps
That expression was not part of your original equation. Also, 'p' was not specifically called a constant nor variable.ok, i understand the completing the square part,
but can someone explain how the next step is..
where does the (1-p)^2 comes about and things like that
thanks
i think i kinda remember it now..
what i did was I put everything on the left side as X and everything on the right as Y
so i have
x^2 - 2pxy = -y^2
then I complete the X on the left side
(x^2 - 2pxy) + (2py/2)^2 = -y^2 + (2py/2)^2
the left side factored out to be
(x-py)^2 = -y^2 + py^2
so then move everything to the left we get
(x-py)^2 + y^2 - py^2
That's the easy part! Long before you learned to "complete the square" you learned that "ax+ ay= a(x+ y)", the "distributive law" in technical terms. There is a y^2 term in both y^2 and -py^2 so : y^2- py^2= y^2(1)- y^2(p)= y^2(1- p).ok, i understand the completing the square part,
but can someone explain how the next step is..
where does the (1-p)^2 comes about and things like that
thanks