- #1
Edwin
- 162
- 0
Consider the function:
g(z(t)) = i*f '(c+it)/(f(c+it) - a)
Where {-d <= t < d}
If we let z = c+it
By change of variables don't we get:
Line integral of g(z(t)) = i ln[f(c+it) - a]
evaluated from t = - d to t = d?
note: ln is the natural log.
Inquisitively,
Edwin G. Schasteen
g(z(t)) = i*f '(c+it)/(f(c+it) - a)
Where {-d <= t < d}
If we let z = c+it
By change of variables don't we get:
Line integral of g(z(t)) = i ln[f(c+it) - a]
evaluated from t = - d to t = d?
note: ln is the natural log.
Inquisitively,
Edwin G. Schasteen