- #1

- 112

- 0

in the reflection principle if f(x) is pure imaginary then the conjugate of f(z)=-f(z*) where z* is the complex conjugate of z.

Any advice on where to start?

thanks

- Thread starter buzzmath
- Start date

- #1

- 112

- 0

in the reflection principle if f(x) is pure imaginary then the conjugate of f(z)=-f(z*) where z* is the complex conjugate of z.

Any advice on where to start?

thanks

- #2

- 112

- 0

sorry I posted in the wrong forum

- #3

Dick

Science Advisor

Homework Helper

- 26,260

- 619

- #4

- 84

- 0

- #5

Dick

Science Advisor

Homework Helper

- 26,260

- 619

?????? I have no idea what that is supposed to mean. The problem is, in fact, about extending the domain of definition of an analytic function. rbzima, aren't you supposed to be working on group theory?

- #6

- 72

- 0

How is this a problem (I see no (implicit) question mark)?

in the reflection principle if f(x) is pure imaginary then the conjugate of f(z)=-f(z*) where z* is the complex conjugate of z.

Any advice on where to start?

thanks

- #7

Dick

Science Advisor

Homework Helper

- 26,260

- 619

He's stating a variant of the Schwarz reflection principle. And trying to prove it.

- #8

- 84

- 0

LOL - This caught my attention, but I managed to finish my group theory stuff. Forgive me if I was wrong, but you don't really have anything to "solve" using what you stated. If f(x) is pure imaginary, it will exist on the imaginary axis, and it's conjugate will then exist on the imaginary axis as well. Maybe I'm just reading the question wrong.?????? I have no idea what that is supposed to mean. The problem is, in fact, about extending the domain of definition of an analytic function. rbzima, aren't you supposed to be working on group theory?

- #9

Dick

Science Advisor

Homework Helper

- 26,260

- 619

- #10

- 6

- 0

Find the Radius of Convergence of the following Power Series:

(a) ∑ as n goes from zero to infinity of Z^n!

(b) ∑ as N goes from zero to infinity of (n + 2^n)Z^n

For (a) I think the radius of convergence is 1 but I'm a bit unsure of that...

- #11

Dick

Science Advisor

Homework Helper

- 26,260

- 619

You are clearly in the wrong thread.

Find the Radius of Convergence of the following Power Series:

(a) ∑ as n goes from zero to infinity of Z^n!

(b) ∑ as N goes from zero to infinity of (n + 2^n)Z^n

For (a) I think the radius of convergence is 1 but I'm a bit unsure of that...

- #12

- 112

- 0

Thanks everyone I think I figured it out

- Last Post

- Replies
- 1

- Views
- 1K

- Last Post

- Replies
- 1

- Views
- 548

- Last Post

- Replies
- 2

- Views
- 1K

- Last Post

- Replies
- 18

- Views
- 2K

- Last Post

- Replies
- 4

- Views
- 1K

- Last Post

- Replies
- 4

- Views
- 1K

- Last Post

- Replies
- 2

- Views
- 1K

- Last Post

- Replies
- 2

- Views
- 862

- Last Post

- Replies
- 1

- Views
- 2K

- Last Post

- Replies
- 4

- Views
- 955