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Complex Eigenvectors

  1. Nov 27, 2006 #1
    Hey,

    I have a quick question that I can not seem to find much of an answer to in my text. When working with a nxn matrix, A, and you find eigenvalues that are complex, I'm confused about how to go about finding the actual eigenvector. I know we compute the null space of A-lambdaI, but that is where I seem to get stuck. For a 2x2, easy enough and I can do it. The problem is when n > 2. Gaussian elimination becomes a ridiculous mess. Is that the only way to do it? When I do substitution I end up with 0 = 0 which makes me think that each row is just some multiple of the other. If this is the case, do I just use any row I want?

    Basically, I'm completely stuck with how to solve the complex matrix.

    Any help would be greatly appreciated! :uhh:
     
  2. jcsd
  3. Nov 28, 2006 #2

    HallsofIvy

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    Well, of course, you get "0= 0". In order to be an eigenvalue, the equations you get with [itex]\lambda[/itex] equal to that eigenvalue, must be dependent so that 0 is not the only solution. I don't know what problem you are doing but Gaussian elimination is the best way to go- expect, of course, to use a TI-93 calculator that will do eigenvectors for you!
     
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