- #1

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^{z}.

As you know you can easily generalize exponents to complex numbers using the fact that:

a

^{z}= e

^{ln(a)[itex]\cdot z[/itex]}

However, as you also know the function lnz is multivalued, i.e. ln(rexp(i[itex]\theta)) = ln(r) + i(\theta[/itex]+2k[itex]\pi[/itex]). Does that mean that the result for a

^{z}should also be multivalued?