- #1

- 6

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Let z=1+2i

Find:

a) 1/z^2

b) 1/z^3

I was thinking just to multiply by the conjugate (1-2i)^2 for (a) and similarly for (b).

Would that be correct in solving it?

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- Thread starter ENGR_student
- Start date

- #1

- 6

- 0

Let z=1+2i

Find:

a) 1/z^2

b) 1/z^3

I was thinking just to multiply by the conjugate (1-2i)^2 for (a) and similarly for (b).

Would that be correct in solving it?

- #2

mfb

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Alternatively, calculate 1/z first, and then calculate powers of that.

As this looks like homework, I moved your thread.

- #3

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Oh thank you!

I apologize if I put it in the wrong thread!

I apologize if I put it in the wrong thread!

- #4

- 237

- 5

Firstly, let's establish what you are actually asking.Oh thank you!

I apologize if I put it in the wrong thread!

For example, the way you wrote it, 1/z^2 = [itex]\frac{1}{z^2}[/itex], NOT [itex](\frac{1}{z})^2[/itex]

EDIT: Please ignore. Complete brain-fart by me there!

Last edited:

- #5

mfb

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Where is the difference?For example, the way you wrote it, 1/z^2 = [itex]\frac{1}{z^2}[/itex], NOT [itex](\frac{1}{z})^2[/itex]

- #6

- #7

HallsofIvy

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