Complex Fourier Series HW

  • Thread starter Aows
  • Start date
  • #1
Aows

Homework Statement


Q:/ Find the complex form of fourier series for the following periodic function whose definition in one period is given below then convert to real trigonometry also find f(0).
f(t)=cos(t/2), notes: (T=2*pi) (L=pi)


Homework Equations


1) f(t)=sum from -inf to +inf (Cn exp(j*n*(pi/L)*t)
2) Cn=(1/2pi) *integration from -L to +L (f(t) exp (-j * n (pi/L)* t) *dt


The Attempt at a Solution


i failed at finding the solution to the Cn coefficient
 

Answers and Replies

  • #2
stevendaryl
Staff Emeritus
Science Advisor
Insights Author
8,919
2,903

Homework Statement


Q:/ Find the complex form of fourier series for the following periodic function whose definition in one period is given below then convert to real trigonometry also find f(0).
f(t)=cos(t/2), notes: (T=2*pi) (L=pi)


Homework Equations


1) f(t)=sum from -inf to +inf (Cn exp(j*n*(pi/L)*t)
2) Cn=(1/2pi) *integration from -L to +L (f(t) exp (-j * n (pi/L)* t) *dt


The Attempt at a Solution


i failed at finding the solution to the Cn coefficient

Well, post what the equations look like when you substitute [itex]cos(t/2)[/itex] in for [itex]f(t)[/itex]. Also, for evaluating the integral, it might help to convert it to exponentials, using:

[itex]cos(x) = \frac{1}{2} (e^{i x} + e^{-ix})[/itex]
 
  • #3
Aows
Well, post what the equations look like when you substitute [itex]cos(t/2)[/itex] in for [itex]f(t)[/itex]. Also, for evaluating the integral, it might help to convert it to exponentials, using:

[itex]cos(x) = \frac{1}{2} (e^{i x} + e^{-ix})[/itex]
Hello,
what do you want me to post ?
 
  • #4
Aows
here is part of the question
7SYajnJ.jpg
 

Related Threads on Complex Fourier Series HW

Replies
5
Views
9K
  • Last Post
Replies
5
Views
3K
  • Last Post
Replies
7
Views
1K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
13
Views
2K
  • Last Post
Replies
5
Views
738
  • Last Post
Replies
0
Views
2K
  • Last Post
Replies
1
Views
473
Top