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Homework Statement
Find the limit :
http://www.a7bk-a-up.com/pic/uDs93333.bmp
http://www.a7bk-a-up.com/pic/zAP94166.bmp
The Attempt at a Solution
http://www.a7bk-a-up.com/pic/g0Q93947.bmp
Homework Statement
result
cos(pi/2)+i*sin(pi/2)=i, not i^(1/2). ???Homework Statement
Find the limit :
http://www.a7bk-a-up.com/pic/uDs93333.bmp
http://www.a7bk-a-up.com/pic/zAP94166.bmp
The Attempt at a Solution
http://www.a7bk-a-up.com/pic/g0Q93947.bmp
Homework Statement
result
The Attempt at a Solution
But what? Isn't the limit still 1?Last Qiustion:
http://www.a7bk-a-up.com/pic/Nww95795.bmp
By imposingcos(pi/2)+i*sin(pi/2)=i, not i^(1/2). ???
Yes,But what? Isn't the limit still 1?
I don't understand that at all.By imposing
I said let w=i===>w^2=-1
Substitute zbar for z in the power series. What's wrong with that?Yes,
Find this limit
Oh No , This can not ; Because sinz*/z* Not AnalyticalSubstitute zbar for z in the power series. What's wrong with that?
Dear: DickSure. |(sin(z*)/z*|=|sin(z)/z|. Because (sin(z)/z)*=(sin(z*)/z*) and |z|=|z*|. So you don't need analyticity, correct?
O. My DodSure. Sorry, I'm not good at the script. afwan.