- #1

emutudeng

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^{2,5i}

Can anyone explain me ? The imaginary part = 3,59 and real part = -4,81

I tried e(x) = cos x + i sin x, but it does not help me.

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- Thread starter emutudeng
- Start date

- #1

emutudeng

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- 0

Can anyone explain me ? The imaginary part = 3,59 and real part = -4,81

I tried e(x) = cos x + i sin x, but it does not help me.

- #2

CAF123

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- #3

Ray Vickson

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Note, however, that the given answers are incorrect as exact statements; they are only

real part ≈ -4.806861693281602289001016742804109986572

and

im part ≈ 3.590832864623738964311128213116973630222

to 40-digit accuracy. No matter how many digits we use we will never be able to write down the

RGV

- #4

emutudeng

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How do I calcuate the values if x=2,5 ?

- #5

Ray Vickson

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How do I calcuate the values if x=2,5 ?

What is stopping you from calculating cos(2,5) and sin(2,5)? (Remember, though, that the '2,5' is in radians, not degrees.)

RGV

- #6

emutudeng

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- #7

CAF123

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Yes.^{-5i}then r = 1 ?

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