- #1
doubleaxel195
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Homework Statement
Find the value of the integral of g(z) around the circle |z-i|=2 in the positive sense when [tex]g(z)=\frac{1}{z^2+4}[/tex]. Answer: pi\2
Homework Equations
Cauchy Integral Formula
[tex]f(z_0)=\frac{1}{2\Pi i}\int \frac{f(z) dz}{z-z_0}[/tex]
The Attempt at a Solution
I tried factoring the denominator by (z-2i)(z+2i), but then f is not analytic when z=+/-2i. So I'm not really sure what to do. I'm not even sure if the Cauchy Integral formula is the right way to go since it evaluates a function at a specific point, not the integral.