- #1

oxon88

- 176

- 1

## Homework Statement

A tubular column supports a mass as shown in the diagram below. A

strain gauge is placed transversely on the outside diameter of the bar to

act as a load measuring device.

The column has an outside diameter of 50 mm and an inside diameter of

40 mm. The modulus of elasticity of the tube material is 250 GN m–2 and

the poison’s ratio is 0.33.

Q. Sketch a graph of the expected strain against the applied load, for a

load range from 0 to 500 kg. Make load the horizontal axis on the

graph and strain the vertical axis.

## Homework Equations

Force,N = M.G

Area,A = ∏/4 . (D

_{o}

^{2}- D

_{i}

^{2}) = ∏/4 (0.05m

^{2}) - (0.04m

^{2}) =

**7.0685834 x10**

^{-4}m^{2}Normal Stress, σ = F / A

Normal Strain, ε = deformation in length / Original Length = l - l

_{0}/ l

_{0}

Young's Modulus, E = σ / ε = 250 GN m–2 =

**250x10**

^{-9}N m^{-2}ε = σ / E

Poisson's Ration, V =

**0.33**

Transversal Strain, ε

_{t}= -νε

## The Attempt at a Solution

Calculate Force, N, for range 0kg to 500kg using using

**F=MG**

Calculate Normal Stress for the range 0kg to 500kg using

**σ = F/A**

Calculate Normal Strain for the range 0kg to 500kg using

**ε = σ / E**

Calculate Transverse Strain for the range 0kg to 500kg using

**ε**

_{t}= -νεPlot a graph using Transverse Strain ε

_{t}Vs Force, N

Does this look anywhere near correct?