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neginf
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Homework Statement
Show log(i^2) and 2*log(i) have different sets of values.
Homework Equations
log z=ln|z|+i*arg z
The Attempt at a Solution
log(i^2) = ln|i^2| + i*arg(i^2)
= ln|-1| + i*(pi + 2*n*pi)
= 0 + i*pi*(1 + 2*n)
= i*pi*(1+2*n)
2*log(i) = 2*(ln|i| + i*arg(i))
= 2*(ln|1| + i*(pi/2 + 2*n*pi))
= 2*(0 + i*(pi/2 + 2*n*pi ))
= i*pi*(1+4*n)
If this isn't right, what did I miss ?