Complex number angle question

[roz77]

I have two complex numbers, let's call them A and B. A=2exp[-ikz], and B=2iexp[-ikz]. I have to figure out the angle of these two numbers, and I am just completely drawing a blank on B. I know that the angle of A is just -kz, but I can't remember how to figure it out for part B. I can't remember what that i in front does.

 

[tiny-tim]

hi roz77!

hint: i = e^i(what?)

 

[roz77]

k and z are just random variables that were in the problem. I know that when its exp[ikz], the angle is kz, but I'm not sure when it's iexp[ikz].

 

[tiny-tim]

no, i mean solve i = e^i(something)

 

[hunt_mat]

$$i=e^{\frac{\pi i}{2}}$$