1. The problem. Given that z= 3-4i Show that z^2 = 3-4i Hence or otherwise find the roots of the equation (z+i)^2=3-4i 2. My attempt. The first part of the problem is strait forward z^2= (2-i)(2-i) then expand to get the desired result. Now the second part (z+i)^2=3-4i. Becomes z^2+ 2zi+i^2 = 3-4i From here on I replace z with 2-i and get nowhere!