# Complex number question

1. Oct 30, 2005

### Reshma

This is a simple problem. Show that:
(-1 + i)7 = -8(1 + i)
where i = sqrt(-1)

I'm able to prove this result by expanding the bracket:
[(-1 + i)3]2(-1 + i)

2. Oct 30, 2005

### HallsofIvy

Staff Emeritus
Okay, PUT it in polar form! Polar form is $r (cos(\theta)+ isin(\theta))$ where r is the "magnitude" of the complex number (distance from 0) which is $\sqrt{(-1)^2+ 1^2}= \sqrt{2}$ for -1+ i and $8\sqrt{2}$ for -8(i+1). You can get $\theta$ by using $\theta= arctan(\frac{Im}{Re})$ but you should be able to see simply by plotting the points. -1+ i corresponds to (-1,1) in the plane so the angle is $\frac{\3pi}{4}$. -(1+i)= -1-i corresponds to (-1, -1) so the angle is $\frac{5\pi}{4}.$.
The seventh power of a complex number corresponds to taking the seventh power of r and multiplying $\theta$ by 7.

3. Oct 30, 2005

### Physics Monkey

Can you write z = -1 + i in polar form? What is the magnitude?

I see Ivy has this handled.

4. Nov 1, 2005

### Reshma

Thanks, HallsofIvy!! That was easy!