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Given that the real and imaginary parts of the complex number [itex]z=x+iy[/itex] satisfy the equation [itex](2-i)x-(1+3i)y=7[/itex]. Find x and y.

The attempt at a solution

I know it's quite simple. Just equate the real and imaginary parts, but i checked and redid it again, but the answer still evades me!

[tex](2x-y-7) + i(-x-3y)=0

\\2x-y-7=x

\\x-y=7\, (1)

\\-x-3y=y

\\4y+x=0\, (2)

\\x=28/5

\\y=-7/5

[/tex]

I replaced in the original equation but i can't get 7 on the L.H.S.

The correct answers: x=3 and y=-1.

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# Homework Help: Complex number

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