- #1

- 44

- 0

z=cos(7pi/6)+i*sin(7pi/6)

2. If i use de movires i get

3. m*7pi/6=7pi/6 + k*2pi

But then i get the value that k=12/7, Which is the wrong formula.

The correct answer is 1+12k for k=0,1,2...

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- Thread starter Dousin12
- Start date

- #1

- 44

- 0

z=cos(7pi/6)+i*sin(7pi/6)

2. If i use de movires i get

3. m*7pi/6=7pi/6 + k*2pi

But then i get the value that k=12/7, Which is the wrong formula.

The correct answer is 1+12k for k=0,1,2...

- #2

SammyS

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What happened to m in your answer?

z=cos(7pi/6)+i*sin(7pi/6)

2. If i use de movires i get

3. m*7pi/6=7pi/6 + k*2pi

But then i get the value that k=12/7, Which is the wrong formula.

The correct answer is 1+12k for k=0,1,2...

Can you show us your work ?

- #3

- 44

- 0

m=1+12k/7

Okay, i got closer to the right answer now

Which is the equation wolfram alpha also get if i post my original equation. So it must be something wrong!!!

1+12k is the correct!!

- #4

SammyS

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You have ##\ m=1+\frac{12}{7}k\,,\ ## & k must be some integer. I suppose from the context of the question that m must also be an integer.

m=1+12k/7

Okay, i got closer to the right answer now

Which is the equation wolfram alpha also get if i post my original equation. So it must be something wrong!!!

1+12k is the correct!!

m will only be an integer if k is an integer multiple of 7 , Right ?

let k = 7n .

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