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Complex numbers polar form

  1. Sep 25, 2012 #1
    Not homework as such, just need some clarification.

    When finding [itex]\alpha[/itex] do you have to take the signs into account when finding tan[itex]^{-1}[/itex] x/a. Does it matter if a or x are negative?

    Next question is about quadrants

    1: [itex]\theta[/itex] = [itex]\alpha[/itex]

    2: [itex]\theta[/itex] = [itex]\pi[/itex] - [itex]\alpha[/itex]

    3: [itex]\theta[/itex] = -[itex]\pi[/itex] - [itex]\alpha[/itex]

    4: [itex]\theta[/itex] = -[itex]\alpha[/itex]

    Based on these (if correct) it seems that I should disregard the sign when finding [itex]\alpha[/itex].

    Is this correct?
  2. jcsd
  3. Sep 26, 2012 #2
    No, signs aren't taken into account while finding [itex]\alpha[/itex].

    I am not sure about the 3 quadrant.
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