Complex numbers polar form

  • #1
Darth Frodo
210
1
Not homework as such, just need some clarification.

When finding [itex]\alpha[/itex] do you have to take the signs into account when finding tan[itex]^{-1}[/itex] x/a. Does it matter if a or x are negative?

Next question is about quadrants

1: [itex]\theta[/itex] = [itex]\alpha[/itex]

2: [itex]\theta[/itex] = [itex]\pi[/itex] - [itex]\alpha[/itex]

3: [itex]\theta[/itex] = -[itex]\pi[/itex] - [itex]\alpha[/itex]

4: [itex]\theta[/itex] = -[itex]\alpha[/itex]

Based on these (if correct) it seems that I should disregard the sign when finding [itex]\alpha[/itex].

Is this correct?
 

Answers and Replies

  • #2
Saitama
4,243
93
Not homework as such, just need some clarification.

When finding [itex]\alpha[/itex] do you have to take the signs into account when finding tan[itex]^{-1}[/itex] x/a. Does it matter if a or x are negative?

Next question is about quadrants

1: [itex]\theta[/itex] = [itex]\alpha[/itex]

2: [itex]\theta[/itex] = [itex]\pi[/itex] - [itex]\alpha[/itex]

3: [itex]\theta[/itex] = -[itex]\pi[/itex] - [itex]\alpha[/itex]

4: [itex]\theta[/itex] = -[itex]\alpha[/itex]

Based on these (if correct) it seems that I should disregard the sign when finding [itex]\alpha[/itex].

Is this correct?

No, signs aren't taken into account while finding [itex]\alpha[/itex].

I am not sure about the 3 quadrant.
 

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