2 Questions:(adsbygoogle = window.adsbygoogle || []).push({});

(1.)Carry out the indicated calculation:

[tex](\frac{-6+2i}{1-8i})^2[/tex]

=[tex]\frac{36-24i+4i^2}{1-16i+64i^2}[/tex]

since [tex]i^2=-1[/tex]

=[tex]\frac{32-24i}{-63-16i}[\frac{-63+16i}{-63+16i}][/tex]

I carry out the math and get an answer of:

[tex]\frac{-2400+1512i}{4225}[/tex]

I must be doing something wrong with the conjugate, as far as i can tell it looks right, but for some reason my signs should be switched to give me the correct answer of:

[tex]\frac{-1632+2024i}{4225}[/tex]

(2.)determine the set of all z satisfying the given equation or inequality:

[tex]|z-2i|<=|z+1+i| & |z|> 4[/tex]

I solved this one down to:

[tex]x^2+y^2-4y+4<=x^2+y^2+2x+2y+2[/tex] & [tex]x^2+y^2>4[/tex]

what do I do to simplify it?

Thanks.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Complex Numbers

**Physics Forums | Science Articles, Homework Help, Discussion**