I have to find the principal root of [tex]\sqrt[3]{8 i}[/tex](adsbygoogle = window.adsbygoogle || []).push({});

But I get stuck at this part

change this to polar coordinates...

[tex]r= \sqrt {x^2 + y^2} [/tex]

which makes [tex]r=8[/tex]

but when I try to find [tex]\theta[/tex]

[tex]\theta = \arctan \frac{y}{x}[/tex]

from the original x = 0 so how do I find [tex]\theta[/tex]?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Complex Numbers

**Physics Forums | Science Articles, Homework Help, Discussion**