- #1

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- 0

1.41 = |(1+1.10iC)/(1+0.1iC)|

Many thanks

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- Thread starter Dirac8767
- Start date

- #1

- 11

- 0

1.41 = |(1+1.10iC)/(1+0.1iC)|

Many thanks

- #2

CompuChip

Science Advisor

Homework Helper

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Maybe multiplying by (1 - 0.1iC)/(1 - 0.1iC) inside the magnitude bars will make your life easier :)

- #3

Mute

Homework Helper

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If z = x + iy, then the magnitude of z is

[tex]|z| = \sqrt{zz^\ast} = \sqrt{x^2 + y^2}[/tex]

where [itex]z^\ast = x - iy[/itex]. One can show that if z and w are complex numbers, then |z/w| = |z|/|w|. You can use this fact to help solve your problem. (This method won't require CompuChip's hint).

- #4

- 11

- 0

If z = x + iy, then the magnitude of z is

[tex]|z| = \sqrt{zz^\ast} = \sqrt{x^2 + y^2}[/tex]

where [itex]z^\ast = x - iy[/itex]. One can show that if z and w are complex numbers, then |z/w| = |z|/|w|. You can use this fact to help solve your problem. (This method won't require CompuChip's hint).

Okay, but im still struggling to see how that will help me solve for C

- #5

Mute

Homework Helper

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Okay, but im still struggling to see how that will help me solve for C

If I gave you the problem

[tex]A = \sqrt{\frac{a^2 + d^2x^2}{b^2 + c^2x^2}}[/tex]

could you solve for x?

My advice helps you make your expression look like this one. If you can solve this one above, you can solve your problem. Can you see how to get from your original expression to a form looking like the one above using the fact that for complex numbers z and w, |z/w| = |z|/|w| and using the definition of the magnitude of a complex number, [itex]|z| = |x + iy| = \sqrt{x^2 + y^2}[/itex]?

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