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Complex numbers

  1. Sep 15, 2013 #1
    Lets say z!=0, and zeC(is complex).
    So for example is z=2+3i.
    z^0=1 => (2+3i)^0=1. I am correct? I know that all numbers in zero make us one,but it works with complex numbers too?
  2. jcsd
  3. Sep 15, 2013 #2


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    It works in the case of complex numbers as well.

    In general, though, the topic of exponentiation and logarithms of complex numbers is a nasty subject, where we have to be very careful when dealing with them.
  4. Sep 15, 2013 #3
    Alright. Thank you !!!
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