Complex numbers

  • Thread starter Hepic
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  • #1
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Main Question or Discussion Point

Lets say z!=0, and zeC(is complex).
So for example is z=2+3i.
z^0=1 => (2+3i)^0=1. I am correct? I know that all numbers in zero make us one,but it works with complex numbers too?
 

Answers and Replies

  • #2
arildno
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Yes.
It works in the case of complex numbers as well.

In general, though, the topic of exponentiation and logarithms of complex numbers is a nasty subject, where we have to be very careful when dealing with them.
 
  • #3
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Alright. Thank you !!!
 

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