- #1
Hepic
- 118
- 0
Lets say z!=0, and zeC(is complex).
So for example is z=2+3i.
z^0=1 => (2+3i)^0=1. I am correct? I know that all numbers in zero make us one,but it works with complex numbers too?
So for example is z=2+3i.
z^0=1 => (2+3i)^0=1. I am correct? I know that all numbers in zero make us one,but it works with complex numbers too?