Why do we need to take the conjugate in complex power calculations?

In summary, complex conjugate is used to get the real power and reactive power in S=VI. This is necessary because the power loss in your system varies with the square of the magnitude of the current.
  • #1
anon6912
21
3
Ive seen in some situations the equation S=VI is
being used with the conjugate of I

IN what situations do you have to take the conjugate and why?
 
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  • #2
The complex power S = P + jQ, where P is the real power and Q is reactive power.

http://en.wikibooks.org/wiki/Circuit_Theory/Complex_Power"
 
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  • #3
Thanks for the reply.
I understand what complex conjugate is.
But I do not know why you have to do it in S=VI
 
  • #4
The principle reason regards loss in your power systems. The power loss in the windings of you motor / transformer / whatever varies to the square of the magnitude of the current. That is

Ploss = R * (Ii^2 + Iq^2)
Where R is your resistance,
Ii is the current that is in phase with your supply voltage
Iq is the current that is out of phase with your supply voltage

That wouldn't be so bad, except that the power being delivered to the shaft of your motor, to the load of your transformer, or to the whatsit of your whatever, is only going to be:
Pload = Ii x V
Where V is the line voltage.

So, Ii contributes nothing to your load, but does a disservice in your windings, wiring, and even out on the utility grids.

As for the complex number, that just gives a simple, phasor notation to keep track of this out of phase current. You can design in both Ii sources and Ii sinks. For example, given that an induction motor has an impedance that has a phase lag, you can drop in a parallel capacitor which will introduce a phase lead. Thus your building (and the utility) don't have to dissipate the power from Ii.

Mike
 
  • #5
A short non-theoretical answer is that the amplitude of the power is the product of the magnitudes of the voltage and current phasors. If you conjugate one, the cross terms go away and you have a Pythagorean norm (sum of squares). If you don't conjugate, you get quadratic cross terms that give the wrong answer for power. Think of S=V*V / R instead if V*I. The right way to square a complex number to get it's magnitude is to multiply it by it's conjugate.

The situations: any time you have a time harmonic formulation with complex phasors or vector phasors. If you need a rigorous theoretical derivation I can give you references.
 
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1. What is complex power conjugate?

Complex power conjugate, denoted as S*, is the complex conjugate of the complex power S. It is a mathematical concept used in electrical engineering to calculate the power in an AC circuit.

2. How is complex power conjugate different from real power?

Complex power conjugate takes into account both the active power (real power) and reactive power (imaginary power). Real power is the average power consumed by a circuit, while reactive power is the power needed to establish and maintain the electric and magnetic fields in an AC circuit.

3. What is the physical significance of complex power conjugate?

Complex power conjugate represents the power that is dissipated or absorbed by a circuit component. It is useful in analyzing the power flow and efficiency of AC circuits.

4. How is complex power conjugate calculated?

Complex power conjugate is calculated by taking the conjugate of the voltage and current values in an AC circuit, and then multiplying them together. The result is a complex number with the unit of volt-amperes reactive (VAR).

5. What is the relationship between complex power conjugate and power factor?

Power factor is the ratio of real power to apparent power (the absolute value of complex power). Complex power conjugate is the imaginary part of apparent power, so it is related to power factor by the equation PF = cosθ = P/S*, where θ is the phase angle between voltage and current.

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