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Complex Power

  1. Dec 27, 2016 #1
    1. The problem statement, all variables and given/known data
    sadasdas.png

    y = 27

    2. Relevant equations

    3. The attempt at a solution
    - I calculated the total impedance.
    - Divide it with the voltage to get the current.
    - Then I use the load impedance to find the voltage load.
    - And I calculated the complex power for the load.

    answer.png

    I am not comfortable with the AC yet.
    Is my solution right?
     
  2. jcsd
  3. Dec 27, 2016 #2

    gneill

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    Staff: Mentor

    Hi Deniz,

    It's very difficult to make out the details of your handwriting in your image. Helpers are more likely to take time to help if your work is easy to see. Can you provide a larger, clear image, or better still (and highly encouraged), type in the solution so that helpers can reference and quote it line by line? The edit panel gives access to the necessary special characters via the ##\Sigma## icon, or you can use LaTeX syntax to present equations in a very polished manner.

    One thing I will mention is, it's not necessary to convert the source function from sine to cosine if you're looking for power values. The angles will sort themselves out as the voltage and current relative phase will be the same regardless of whether the input is a sine or cosine. It's dictated by the impedance angles.
     
  4. Dec 27, 2016 #3
    Sorry for the quality gneill, this has a better resolution.

    Untitled.png
     

    Attached Files:

  5. Dec 27, 2016 #4

    gneill

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    Staff: Mentor

    I'm looking at your calculation of ##Z_{eq}##, and while the magnitude looks good I'm not happy with the phase angle. What are your rectangular components for ##Z_{load}##?
     
  6. Dec 27, 2016 #5

    gneill

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    Staff: Mentor

    Are you specifying your angles in degrees or radians? You don't make this clear in your work.
     
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