1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Complex product

  1. Nov 14, 2008 #1
    [tex]Re [e^{iE_{0}t/\hbar} \cdot e^{-iE_{1}t/\hbar}] = Re[ e^\frac{it}{\hbar}(E_{0}-E_{1})] = cos \frac{t}{\hbar}(E_{o}-E_{1})[/tex]

    Correct?
     
    Last edited: Nov 14, 2008
  2. jcsd
  3. Nov 14, 2008 #2

    Mark44

    Staff: Mentor

    Check your multiplication. You ended up with two terms, each with two factors. You should have ended up with four terms, each with two factors.

    Another approach is to multiply the two exponentials first before converting them to cos X + i sin X. Remember that e^A * e^B = e^(A + B).
     
  4. Nov 14, 2008 #3
    I've updated it. Is this what you meant?
     
  5. Nov 14, 2008 #4

    Mark44

    Staff: Mentor

    That's what I meant in "another approach." Also, your answer looks to be correct this time.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Complex product
Loading...