- #1
tasuzuki
- 1
- 0
√(2gH)(M-m)=mV+M√((2gH(M+m)-mV^2)/M)
Solve for V in terms of given terms.
Solve for V in terms of given terms.
Welcome to PH Forums.tasuzuki said:√(2gH)(M-m)=mV+M√((2gH(M+m)-mV^2)/M)
Solve for V in terms of given terms.
A complex quadratic equation is an algebraic equation in the form of ax^2 + bx + c = 0, where a, b, and c are complex numbers and x is the variable. It can have two complex solutions, which are numbers of the form a + bi, where a and b are real numbers and i is the imaginary unit.
To solve a complex quadratic equation, you can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a. First, determine the values of a, b, and c in the equation. Then, substitute those values into the formula to find the solutions for x. You may need to simplify the square root to get the final answer in the form of a complex number.
The discriminant of a complex quadratic equation is the expression under the square root in the quadratic formula, b^2 - 4ac. It helps determine the nature of the solutions to the equation. If the discriminant is positive, there are two distinct real solutions. If it is zero, there is one real solution. If it is negative, there are two complex solutions.
To graph a complex quadratic equation, plot the solutions on the complex plane. The real part of the solution represents the x-coordinate, and the imaginary part represents the y-coordinate. You can also plot the equation as a curve on the plane, using the vertex, focus, and directrix of the parabola, which can be found using the formula y = ax^2 + bx + c.
Complex quadratic equations can be graphed on the complex plane, which is a 2-dimensional plane with the real numbers represented on the horizontal axis and the imaginary numbers represented on the vertical axis. The solutions to the equation can be plotted as points on this plane, giving a visual representation of the solutions and the shape of the equation's graph.