1. Hi I posted a previous question on this forum and it was answered well but I had another question about complex solutions/roots. for example if i have a question like z^2 = 1e^(j)(pie) z = 1e^(j)(pie + 2kpie)^1/2 k =0,1 1. z = 1e^(j)(pie/2 ) = 0 + j 2. z = 1e^(j)(3pie/2) = 0 - j if I test these solutions (0+j)(0+j) = -1 , (0 - j)(0 - j) = -1 they are correct but my question is are those angles correct???? another way to solve that question seems to be z^2 = 1e^(j)(-pie) z = 1e^(j)(-pie + 2kpie)^1/2 k =0,1 1. z = 1e^(j)(-pie/2 ) = 0 - j 2. z = 1e^(j)(pie/2) = 0 + j if i go backwards 0 + j = 1e^(j)(-pie/2 ) and 0 - j = 1e^(j)(pie/2) so which angles are correct??? Like on an exam I don`t really know which angles I would write!