How much AgBr could dissolve in 1.0 L of 0.40 M NH3? Assume that Ag(NH3)2+ is the only complex formed. [Kf=1*108 ; Ksp=5*10-13]
The Attempt at a Solution
Let Ag+ and Br- formed from AgBr be x. Since Ag+ form a complex with NH3, let the amount of Ag+ remaining be x-y, hence amount of NH3 remaining is 0.4-2y and amount of complex formed is y.
I hope my equations are correct.
Now the trouble is solving the equations. I can easily plug them in a calculator and get the answer but I want to know if there is a way to do this problem without using one.
Since Kf is so large, I think that ammonia will be almost completely used and hence, y=0.2 M but I don't see if this helps or if my assumption is correct.
Any help is appreciated. Thanks!