- #1

- 80

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[tex]\frac{v_2+3v_1^2-2v_1v_2}{3v_2^2-3v_1^2-2v_2v_1}[/tex]

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- Thread starter Brunno
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- #1

- 80

- 0

[tex]\frac{v_2+3v_1^2-2v_1v_2}{3v_2^2-3v_1^2-2v_2v_1}[/tex]

- #2

- 80

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What i meant was simplify the algebra to this one:

[tex]\frac{v_2[3v_1+v_2]}{[v_1+3v_2]}[/tex]

[tex]\frac{v_2[3v_1+v_2]}{[v_1+3v_2]}[/tex]

- #3

- 1,233

- 18

I don't think they are the same expression...

- #4

- 80

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[tex]\frac{2(v_1+v_2)-(v_2-v_1)}{(v_2-v_1)}[/tex]* [tex]\frac{v_2-v_1}{2(v_1+v_2)+(v_2-v_1)}[/tex]

- #5

- 1,233

- 18

Where are you quoting from? None of this follows to me.

- #6

- 80

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Three tourists gathered in one place and having a bike that can carry only two people ever need to get to a tourist destination as quickly as possible.The A tourist

The three arrive simultaneously to the turistic centre.

A average speed v1 is as pedestrian and cyclist as v2 average speed that the tourists will the total route.

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